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Algebraic Manipulation - Quiz 2   Last unanswered question  Question  Next unanswered question

Question 1 lion

Which of the following correctly makes  y    the subject of   3y- 2x = 5?
a)        2
y = 5- 3x .    b) y = 5 + 2x.
       3
c)     5+ 2x
y = ------.
      3    d) y = 5+-3x-.
      2

 

Not correct. Choice (a) is false.
Try again, you haven’t performed the operations in the right order, watch the signs.
Not correct. Choice (b) is false.
Try again, you haven’t performed the operations in the right order.
Your answer is correct.
If   3y- 2x = 5    then   3y = 5+ 2x    and
y = 5+-2x-.
      3
Not correct. Choice (d) is false.
Try again, you have confused the coefficients of  x    and  y.
Question 2 lion

Is the following factorized correctly?

        2      2           2
2x y- 4xy  + 6y = 2y(x - 2xy +3).
a) True.   b) False.

 

Your answer is correct.
Yes this is factorized correctly.
Not correct. Choice (b) is false.
Try again, this is factorized correctly.
Question 3 lion

Which of the following are correctly factorized?
There may be more than one correct answer.
a) 5a2b3 - 18a3b2 = a2b2(5- 18a).
b) 9ab2 - 3a2b3 = 3ab2(3- ab).
c) 2axc +2ac - 4acd = 2ac(x + 1- 2d).
d) ab+ a2b- ab2 = ab(a - b).
e) 8a2b2c+ 3a2bc = abc(8ab+ 3a).

 

There is at least one mistake.
For example, choice (a) should be false.
5a2b3 - 18a3b2 = a2b2(5b - 18a).
There is at least one mistake.
For example, choice (b) should be true.
There is at least one mistake.
For example, choice (c) should be true.
There is at least one mistake.
For example, choice (d) should be false.
ab+ a2b - ab2 = ab(1 +a - b).
There is at least one mistake.
For example, choice (e) should be true.
Your answers are correct
  1. False. 5a2b3 - 18a3b2 = a2b2(5b - 18a).
  2. True.
  3. True.
  4. False. ab+ a2b - ab2 = ab(1 +a - b).
  5. True.
Question 4 lion

Which of the following correctly makes   μ    the subject of   z = x---μ?
     σ
a)     x - z
μ = -----.
      σ    b) μ = x- zσ .
c) μ = zσ - x.    d) μ = x-- z.
    σ

 

Not correct. Choice (a) is false.
Try again, you cannot just swap the  z    and the  μ .
Your answer is correct.
zσ = x- μ    so   - μ = - x +zσ .
Hence   μ = x- zσ.
Not correct. Choice (c) is false.
Try again, you have found   - μ.
Not correct. Choice (d) is false.
Try again, you have not performed the operations in the correct order.
Question 5 lion

Which of the following makes  n    the subject of the formula       ∘-p(1---p)
e = z  --n----?
a)     zp(1- p)
n = ----e---.    b)     ----e2----
n = z2p(1- p) .
c)     z2p(1--p)
n =     e2   .    d)      ∘ p(1--p)-
n = z  -------.
          e

 

Not correct. Choice (a) is false.
Try again, you haven’t dealt with the square root sign.
Not correct. Choice (b) is false.
Try again, you have found  1-
n .
Your answer is correct.
If        ∘ p(1---p)-
e = z  ---n---    then         p(1- p)
e2 = z2---n---    and
    z2p(1- p)
n = ----2----.
        e
Not correct. Choice (d) is false.
Try again, you can’t just swap  n    and  e.