 Simultaneous Equations - Quiz 3 Question Question 1 Solve the following system of simultaneous equations (1) (2)
Which of the following is the solution for a) b) c) d) Not correct. Choice (a) is false.
Try again, this is the value of Not correct. Choice (b) is false.
Try again. You need to add the equations together to eliminate Solving by elimination we add the two equations and get and hence This then gives since by substitution into (1) we have and we check (2) and see that So we have that and Not correct. Choice (d) is false.
Try again. You need to add the equations together to eliminate Question 2 Solve the system of equations below. (1) (2)
Which of the following is the solution for a) b) c) d) Not correct. Choice (a) is false.
Try again, this is the value of n.
Not correct. Choice (b) is false.
Try again, check the sign.
Not correct. Choice (c) is false.
Try again, multiply (1) by 2 to eliminate and solve for then ﬁnd Solving by elimination we multiply (1) by 2 to give (3)
Subtract (2) from (3) to give Substitute into (1) and Check in (2) and Hence and Question 3 Consider the simultaneous equations below (1) (2)
Which of the following are the correct steps to eliminate from the equations?
 a) Multiply (1) by 2 and (2) by 5 and then add the equations. b) Multiply (1) by 3 and (2) by 2 and then add the equations. c) Multiply (1) by 2 and (2) by -3 and then add the equations. d) Multiply (1) by 3 and (2) by -2 and then add the equations.

Not correct. Choice (a) is false.
Try again, this eliminates Not correct. Choice (b) is false.
Try again, you would need to subtract the equations to eliminate Not correct. Choice (c) is false.
Try again, this gives These steps give  and Question 4 Which of the following is the solution for a to the simultaneous equations (1) (2)
 a) b) c) d) Not correct. Choice (a) is false.
Try again. To eliminate we multiply (1) by 2 and (2) by 3 and add the equations.
Not correct. Choice (b) is false.
Try again. To eliminate we multiply (1) by 2 and (2) by 3 and add the equations.
Not correct. Choice (c) is false.
Try again. To eliminate we multiply (1) by 2 and (2) by 3 and add the equations.
Solving by elimination we multiply (1) by 2 and (2) by 3. (3) (4)
Add equations (3) and (4) and get and hence Substitute into equation (1) and get so Check in equation (2) and 3(2)-2(-3)=12 and we have and Question 5 Consider the system of simultaneous equations below (1) (2)
Which of the following is the correct simpliﬁcation of the problem and solution for to the system?
 a)  and b)  and c)  and d)  and Not correct. Choice (a) is false.
Try again, you the correct equations but you have solved for Not correct. Choice (b) is false.
Try again, you have not multiplied 12 by 5. These are the wrong equations but it is the correct solution for to the wrong equations.
Expanding the equations we have  Collecting like terms we have  Dividing the last equation by 4 we have the required equations (3) (4)
Multiplying (4) by 3 we have (5)
Subtract (3) from (5) and we have Substituting into (4) we have Check in (1) and we have Hence Not correct. Choice (d) is false.
Try again, you have not multiplied 12 by 5. These are the wrong equations but it is the correct solution to the wrong equations.